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RE: Question: IPv6 Addressing [7:132163] posted 07/31/2008
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Hi all,

I agree with Ken, but I'd like to understand the reason behind the /60 ? How
did you got this conclusion?

-----Mensagem original-----

               De: "Matlock, Kenneth L" 
Assn.: RE: Question: IPv6 Addressing [7:132163]
Data: Qui 31 Jul 2008 12:29
Tamanho: 2K
Para: cisco@xxxxxxxxxxxxxx

I believe what he means, is that :CD3: is interpreted as :0CD3: , not as

Just like in real life, any leading zeroes are meaningless, but trailing
zeros are significant. Such as 100 in decimal is the same as 0100, not
1000 (add a trailing 0 completely changes the value, whereas a leading 0
doesn't change anything).

Ken Matlock
Network Analyst
(303) 467-4671
-----Original Message-----
From: nobody@xxxxxxxxxxxxxx [mailto:nobody@xxxxxxxxxxxxxx] On Behalf Of
John Lopez
Sent: Thursday, July 31, 2008 9:24 AM
To: cisco@xxxxxxxxxxxxxx
Subject: Re: Question: IPv6 Addressing [7:132163]

Thanks for the reply Sir. Sorry  I'm still confused tough. I know when 
to omit zeros in an IPv6 address. What do you mean by "anything missing 
is presumed 0's on the left side?" Shouldn't it be right side? Thank you

so much Sir.


Scott Morris wrote:

> IPv6 is broken up into chunks of 4 characters.  So your adrress:
> 12AB:0000:0000:CD3 as you gave it does indeed represent a /60 (or it's
> assumed anyway since the rest of the bits are missing!)
> You can collapse "0000" into "0" because you are allowed to lose
> 0's between colons.  That means that "0CD3" can collapse to simply
> even as a /60, we need to place the last 0 to make the chunk complete.
> So 12AB:0:0:CD30::/60 would be your correct answer below which is D.
> same version spelled out is A, but while accurate in binary, it's a
> way to write it!  :)
> As for the dividing part, you don't NEED to go on any ":" boundary.
> like in IPv4 you can make your mask anything you want.
> So 12AB:0:0:CD30::/64 would be a "standard" network mask.  But there's
> reason you can't have 12AB:0:0:CD30:0:0:0:00F0/126 on a point to point
> (where we see /30's today).
> But each quartet as you call it needs to have 4 characters to be
> Anything missing is presumed 0's on the LEFT side.
> Cheers,
> Scott Morris, CCIE4 #4713, JNCIE-M #153, JNCIS-ER, CISSP, et al.
> Senior CCIE Instructor
> smorris@xxxxxxxxxxxxxxxxxxxxxx
> Internetwork Expert, Inc.
> Toll Free: 877-224-8987
> Outside US: 775-826-4344
> Knowledge is power. 
> Power corrupts. 
> Study hard and be Eeeeviiiil......
> -----Original Message-----

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