Re: bgp problem posted 10/23/2006
Hi guys What scott says is right but i have no said the same question but
only similar question.
On 10/23/06, WorkerBee <ciscobee@xxxxxxxxx> wrote:
> You can force R2 to initial the BGP peering by applying ACL to the PIX
> ACL inside
> deny tcp host R1_Lo host R2_Lo eq 179
> ACL outside
> permit tcp host R2_Lo host R1_Lo eq 179
> Hence, the ACL will force the peering R1 (179) <--------> R2 (High Port).
> On 10/23/06, emmanuel daniel <emmanueldan@xxxxxxxxx> wrote:
> > Hi
> > I took my sec exam last week and i couldnt pass mainly i got less points
> > bgp. i Wantt to know where i screwed up can any one help me out here is
> > problem the qustion was some what similar to this
> > R1 e0/0 184.108.40.206 -------- (inside 220.127.116.11) pix (outside
> > )---------18.104.22.168 e0/0 r2
> > lo 22.214.171.124
> > lo
> > 126.96.36.199
> > (BGP AS
> > 54)
> > (BGP AS 55)
> > the question is r1 which is bgp as 54 wants make an ebgp peering with r2
> > with is in as 55. using thee loopbacks and make the peering such that
> > always uses a foreign port of 179. i thought its given just to confuse
> > and i didnt solve it bec default bgp port is 179.
> > Regards
> > Emmanuel.
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