Hi,
Look at the topology table:
> P 5.5.5.5/32, 1 successors, FD is 156160
> via 142.1.65.5 (156160/128256), FastEthernet2/0
> via 142.1.56.5 (386560/128256), FastEthernet0/0
The numbers in the parathesis means (FD/AD). The rule is: routes in
topology table if AD < minimum FD, and will install to routing table is FD <
variance * minimum FD. Therefore in your case you have to pick a variance,
so that 386560 < variance * 156160.
HTH
William Chen
----- Original Message -----
From: "k c" <jwongccie@xxxxxxxxxxxx>
To: <ccielab@xxxxxxxxxxxxxx>
Sent: Saturday, March 27, 2004 11:22 PM
Subject: EIGRP - Variance
> Dear All,
>
> How to calculate the variance used in eigrp to allow the routing table
showing two possible routes using "sh eigrp topology" result? I have tried
useing variance = 2, but fail.
>
> 5.0.0.0/32 is subnetted, 1 subnets
> D 5.5.5.5 [90/156160] via 142.1.65.5, 00:00:04, FastEthernet2/0
>
> P 5.5.5.5/32, 1 successors, FD is 156160
> via 142.1.65.5 (156160/128256), FastEthernet2/0
> via 142.1.56.5 (386560/128256), FastEthernet0/0
>
> Thanks,
> JWong
>
>
>
> %21~'^!B6<:q!B$p,P,P...
> .v:)9aAn 1!$_3sC4
> http://ringtone.yahoo.com.hk/
>
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