Ratios work just like fractions. Look for the lowest common denominator.
It is easy to see that 2/4 is the same as 1/2. Thus 25/15 = 5/3.
He just noticed that the numbers in the original ratios all ended in 0
or 5, which (as you have pointed out) means they are divisible by 5.
> -----Original Message-----
> From: nobody@xxxxxxxxxxxxxx [mailto:nobody@xxxxxxxxxxxxxx] On
> Behalf Of Jason Cash
> Sent: Sunday, June 01, 2003 1:22 PM
> To: 'Nguyen Hoang Long'; ccielab@xxxxxxxxxxxxxx
> Subject: RE: Custom Queue Confusion
>
>
> That actually is the correct answer, but how did you come to get:
>
> 30:30:25:15 = 6:6:5:3 ?
>
> How did you know to divide by 5 to get 6:6:5:3? Or did you
> use some other
> calculation?
>
> -----Original Message-----
> From: nobody@xxxxxxxxxxxxxx [mailto:nobody@xxxxxxxxxxxxxx] On
> Behalf Of
> Nguyen Hoang Long
> Sent: Sunday, June 01, 2003 2:54 AM
> To: Jason Cash; ccielab@xxxxxxxxxxxxxx
>
> Hi Jason,
>
> I would do by this way for exact ratio:
>
> IP:SNA:IPX:telnet = 30:30:25:15 = 6:6:5:3
>
> therefore:
>
> IP = 1500x6 = 9000 (30%)
>
> SNA = 1500x6 = 9000 (30%)
>
> IPX = 1500x5 = 7500 (25%)
>
> Telnet = 1500x3 = 4500 (15%)
>
> Since we're using new IOS, which permits the router to borrow
> from the next
> queue for a current queue, your calculation method is not
> necessary. I
> prefer a more simple method.
>
> Long
> ----- Original Message -----
> From: "Jason Cash" <cash2001@xxxxxxxxxx>
> To: <ccielab@xxxxxxxxxxxxxx>
> Sent: Sunday, June 01, 2003 12:28 PM
> Subject: Custom Queue Confusion
>
>
> > I am getting really confused on the custom queuing! I have
> looked over
> the
> > previously provided links, but those examples don't address
> the problem I
> am
> > having. Whereas I am instructed:
> >
> >
> >
> > IP traffic 30% bw
> >
> > SNA traffic 30% bw
> >
> > IPX traffic 25% bw
> >
> > Telnet traffic 15% bw
> >
> >
> >
> > Here is what I do (average pkt 1500)
> >
> > 1) For each queue, divide the percentage of bandwidth you
> want to allocate
> > to the queue by the packet size, in bytes.
> >
> > 30/1500 = .02
> >
> > 30/1500 = .02
> >
> > 25/1500 = .0166
> >
> > 15/1500 = .01
> >
> >
> >
> > 2) Normalize the numbers by dividing by the lowest number:
> >
> > .02/.01 = 2
> >
> > .02/.01 = 2
> >
> > .0166/.01 = 1.66
> >
> > .01/.01 = 1
> >
> >
> >
> > 3) A fraction in any of the ratio values means that an
> additional packet
> > will be sent. Round up the numbers to the next whole number
> to obtain the
> > actual packet count.
> >
> > IP = 2
> >
> > SNA = 2
> >
> > IPX = 2
> >
> > Telnet = 1
> >
> >
> >
> > 4) Convert the packet number ratio into byte counts by
> multiplying each
> > packet count by the corresponding packet size.
> >
> > IP = 1500x2 = 3000
> >
> > SNA = 1500x2 = 3000
> >
> > IPX = 1500x2 = 3000
> >
> > Telnet = 1500x1 = 1500
> >
> >
> >
> > Now here is one place I get lost. IPX byte count is the
> same as IP and
> SNA
> > and I know that can't be right, but what do I do? 2 is the
> only multiple
> to
> > go by.
> >
> >
> >
> > 5) To determine the bandwidth distribution this ratio
> represents, first
> > determine the total number of bytes sent after all three queues are
> > serviced:
> >
> > Based on my info above I get: 3000+3000+3000+1500= 10500
> >
> >
> >
> > 6) Then determine the percentage of the total number of
> bytes sent from
> each
> > queue:
> >
> > IP = 3000/10500 = .28 (28%)
> >
> > SNA = 3000/10500 = .28 (28%)
> >
> > IPX = 3000/10500 = .28 (28%)
> >
> > Telnet = 1500/10500= .14 (14%)
> >
> >
> >
> > This adds up to 98%. So I will wait for some advice before
> I proceed.
> > Basically, when I a queue is rounded up and is equal to a
> greater queue,
> how
> > is that queues byte count determined?