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Re: OSPF Redistribution Challenge posted 01/22/2001
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Can anyone tell me what is wrong with Bill's answer?

-Mike

At 09:19 AM 1/22/01 -0800, Bill Dellamar wrote:
>I don't have a rack to test this, but this would be my
>first guess.
>
>How about this on R3:
>router ospf 1
>default-information-originate route-map gen-default
>!
>route-map gen-default permit 10
>match ip address 1
>!
>access-list 1 permit 135.5.192.0 0.0.0.3
>
>Bill
>
>--- Mike McSpedon <mike@xxxxxxxxxxxxxx> wrote:
> > Here's a challenge:
> >
> > r1e0===e0r2s0====s1r3s0=======s1r4e0
> >
> > r1e0: 170.10.1.1 /24
> > r2e0: 170.10.1.2 /24
> > r2s0:170.10.255.1 /30
> > r3s1:170.10.255.2 /30
> > r3s0: 135.5.192.1 /30
> > r4s1: 135.5.192.2 /30
> > r4e0: 135.5.112.0 /24
> >
> > Loopbacks:
> > r3: 192.168.3.1
> > r4: 192.168.4.1
> >
> > 1. Routers 1, 2, and the 3 are routing IP via ISIS.
> > 2. OSPF is running only on the serial link between
> > routers 3 and 4 and on
> > the Ethernet on r4  (all Area 0).
> > 3 . Perform mutual redistribution between ISIS and
> > OSPF on r3 .
> > 4. Advertise a default route to from r3 to r4 if
> > AND ONLY if  r2 is
> > reachable.  Do not use a default route in the ISIS
> > domain. Only advertise
> > the address above from the ISIS domain to the OSPF
> > domain.
> >
> > The answer is on the CD.
> >
> > Enjoy!
> > -Mike
> >
> >
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