hello,
thanks to everyone who replied. your help is greatly appreciated. sh ip
route looks like:
highland#sh ip route
Codes: C - connected, S - static, I - IGRP, R - RIP, M - mobile, B - BGP
D - EIGRP, EX - EIGRP external, O - OSPF, IA - OSPF inter area
E1 - OSPF external type 1, E2 - OSPF external type 2, E - EGP
i - IS-IS, L1 - IS-IS level-1, L2 - IS-IS level-2, * - candidate
default
Gateway of last resort is not set
10.0.0.0 255.255.255.0 is subnetted, 1 subnets
C 10.1.1.0 is directly connected, Ethernet0
192.168.0.0 255.255.255.252 is subnetted, 1 subnets
C 192.168.0.4 is directly connected, Serial0
R 192.168.2.0 [120/1] via 192.168.0.6, 00:00:27, Serial0
highland#
psashit#sh ip route
Codes: C - connected, S - static, I - IGRP, R - RIP, M - mobile, B - BGP
D - EIGRP, EX - EIGRP external, O - OSPF, IA - OSPF inter area
E1 - OSPF external type 1, E2 - OSPF external type 2, E - EGP
i - IS-IS, L1 - IS-IS level-1, L2 - IS-IS level-2, * - candidate
default
Gateway of last resort is not set
R 10.0.0.0 [120/1] via 192.168.0.5, 00:00:25, Serial0
192.168.0.0 255.255.255.252 is subnetted, 1 subnets
C 192.168.0.4 is directly connected, Serial0
C 192.168.2.0 is directly connected, Ethernet0
psashit#
after speaking w/ someone in the field, he mentioned that i did not have to
include the ethernet interfaces in the RIP routing process. he was trying
to explain to me that the 192.168.0.0 network statement was the only needed
to get the routers to share tables and subnets.
still trying to wrap my brain around this one. i hope to exclude the
ethernet interfaces in my test lab, and see what happens.
however, any other insight would very very welcome.
thanks again, everyone.
regards,
mike g.
seattle, wa
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