> If given a network address of 192.168.100.0, subnet mask
> 255.255.255.240,
> select the hosts allowable (choose three).
>
> ( ) 192.168.100.16
> ( ) 192.168.100.239
> ( ) 192.168.100.151
> ( ) 192.168.100.176
> ( ) 192.168.100.61
> ( ) 192.168.100.49
>
> My answer - none of them. I wrote that in after clicking the
> comment button
> on the bottom right corner of the screen. The allowable host range is
> 192.168.100.1 to 192.168.100.14.
Actually, you are wrong. Note that network and subnet are not the
same. 192.168.100.0 is a C class network that can be subnetted to 13
different subnets using given mask (or 15 with 0 and "broadcast" subnets):
192.168.100.0-15
192.168.100.16-31
192.168.100.32-63
192.168.100.64-79
192.168.100.80-95
192.168.100.96-111
192.168.100.112-127
192.168.100.128-143
192.168.100.144-159
192.168.100.160-175
192.168.100.176-191
192.168.100.192-207
192.168.100.208-223
192.168.100.224-239
192.168.100.240-255
With this in mind, valid hosts are:
( ) 192.168.100.16 <- subnet 192.168.100.16/28
( ) 192.168.100.239 <- broadcast for 192.168.100.224/28
(*) 192.168.100.151
( ) 192.168.100.176 <- subnet 192.168.100.176/16
(*) 192.168.100.61
(*) 192.168.100.49
Marko.
P.S. I think I made some calculation error with those 13 and 15 subnets, but
I'm totally unable to find out what :-(
Message Posted at:
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