You're going to have convert the IP and subnet to binary notation thus
getting:
201.110.65.0 -> 11001001.01101110.01000001.00000000
255.255.255.240 -> 11111111.11111111.11111111.11110000
Mulitply through ---------------------------------------------------
11001001.01101110.01000001.11110000
To detemine the number hosts, you count the trailing zeros which is 4.
# of hosts = 2*nth power - 2
nth power = number of trailing zeros
total hosts = 14
Maybe someone can explain how getting 7 subnets is derived.
Anton
----- Original Message -----
From:
To:
Sent: Friday, October 05, 2001 12:17 PM
Subject: Q again... [1:6342]
> Hello guys,
>
> Back with my subnetting questions and I need your help again.
>
> Please explain how the answer to this question was arrived at.
>
> 1. Given the class c address 201.110.65.0 design a subnet mask to support
7
> subnets with 14 hosts per subnet.
>
> a) 255.255.255.240
> b) 255.255.255.0
> c) 255.255.255.248
> d) 255.255.255.224
>
> Boson test says the answer is A. (255.255.255.240). Pls explain.
>
> Much Appreciated.
> Tee.
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