Tee,
255.255.255.240 splits the Class C into blocks of 16 addresses (14 useable).
256/16 = 16 subnets. The block of 16 is exactly the size for the number of
hosts you need per subnet even if it does split it into more subnets than
you need. 255.255.255.248 only gives you 6 host addresses. 255.255.255.0
is a full class C. Try 255.255.255.224 which gives you blocks of 32
addresses (30 useable) 256/32 = 8 subnets. I would think that would work
as well. It encompasses your requirement for 14 hosts per subnet (actually
giving you more than that) and meets your requirements for number of subnets
7 (actually giving you 8). You only thing I can think of is that they were
looking for 14 hosts per subnet. Pretty ambiguous question.
Jason E. Ealey
Senior Design Engineer
Broadslate Networks, Inc
-----Original Message-----
From: Mailtee@xxxxxxx [mailto:Mailtee@xxxxxxx]
Sent: Friday, October 05, 2001 3:17 PM
To: associate@xxxxxxxxxxxxxx
Subject: Q again... [1:6342]
Hello guys,
Back with my subnetting questions and I need your help again.
Please explain how the answer to this question was arrived at.
1. Given the class c address 201.110.65.0 design a subnet mask to support 7
subnets with 14 hosts per subnet.
a) 255.255.255.240
b) 255.255.255.0
c) 255.255.255.248
d) 255.255.255.224
Boson test says the answer is A. (255.255.255.240). Pls explain.
Much Appreciated.
Tee.
Message Posted at:
http://www.groupstudy.com/form/read.php?f=1&i=6343&t=6342
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