The correct answer is D
Given the IP address and subnet mask, the 3rd byte is being used
for subnetting. To match subnets 8 - 15 start with the IP address
172.16.8.0 and mask out the 3 low order bits in the 3rd byte and then
mask out the entire 4th byte resulting in a wildcard mask of 0.0.7.255.
To Find Wildcard Mask, Take the HIGHER minus the Lower:
172.016.015.255
-172.016.008.000
wildcard 000.000.007.255
ER
----- Original Message -----
From: "Ednilson Rosa"
To:
Sent: Thursday, March 01, 2001 10:44 PM
Subject: Question about Wildmasks [1:2272]
Hello ALL,
I found this question on a test from Boson and didn´t agree with their
answer. Which you you think it´s the correct answer for it??
Given the IP address 172.16.8.0 255.255.255.0, what is the wildcard
mask that will match subnets 172.16.8.0 - 172.16.15.0 and all the
hosts on the subnets?
A.) 0.0.7.0
B.) 0.0.0.127
C.) 0.0.255.255
D.) 0.0.7.255
E.) 0.0.0.64
F.) 0.0.0.7
I´ll give you their answer in a later message.
Thanks,
Ednilson Rosa
Analista de Suporte Técnico
CPM S/A - Filial Salvador - BA
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